Solve Java exception error: Problem

It is an exception class in Java, belongs toBag.

This exception is thrown when the program tries to use an unresolved address. The following is a detailed explanation for you:

Exception meaning

In network programming, an address usually refers to a combination of an IP address and a port number, which is used to identify a node in the network (such as a server or client).

To communicate with a network node, the host name (such as a domain name) needs to be parsed into the corresponding IP address.

If there is a problem during this analysis process, or if an invalid address is used directly, it will be thrown.UnresolvedAddressExceptionabnormal.

Possible scenarios

1. Incorrect IP address format

When the IP address used is incorrect, the resolution cannot be completed.

For example, the range of an IP address is beyond the legal range (e.g.256.256.256.256), or an incomplete IP address was used.

import ;
import ;
import ;

public class InvalidIPExample {
    public static void main(String[] args) {
        try {
            DatagramChannel channel = ();
            // Incorrect IP address format            InetSocketAddress address = new InetSocketAddress("256.256.256.256", 8080); 
            ByteBuffer buffer = ("Hello".getBytes());
            (buffer, address);
        } catch (Exception e) {
            ();
        }
    }
}

2. DNS resolution failed

If you are using a domain name instead of an IP address, Java will try to resolve the domain name to the corresponding IP address through DNS (domain name system).

If the DNS server is configured incorrectly, there is a problem with the network connection, or the domain name itself does not exist, it will cause the resolution to fail.

import ;
import ;
import ;

public class DNSFailureExample {
    public static void main(String[] args) {
        try {
            DatagramChannel channel = ();
            // Domain name that does not exist            InetSocketAddress address = new InetSocketAddress("", 8080); 
            ByteBuffer buffer = ("Hello".getBytes());
            (buffer, address);
        } catch (Exception e) {
            ();
        }
    }
}

3. Uninitialized address object

In the code, this exception may also be raised if the address object passed to the network operation method is not initialized correctly.

import ;
import ;
import ;

public class UninitializedAddressExample {
    public static void main(String[] args) {
        try {
            DatagramChannel channel = ();
            InetSocketAddress address = null;
            ByteBuffer buffer = ("Hello".getBytes());
            // Passed an uninitialized address object            (buffer, address); 
        } catch (Exception e) {
            ();
        }
    }
}

Solution

• Check the address format: Make sure the IP address or domain name you are using is in the correct format.
• Verify DNS configuration: If you use a domain name, you must ensure that the DNS server is configured correctly and that the domain name is valid.
• Correctly initialize the address object: Before using the address object, make sure it has been initialized correctly.

Summarize

The above is personal experience. I hope you can give you a reference and I hope you can support me more.