Detailed description of the Python standard library datetime date module

# coding:utf-8
import datetime
now_date = (2022, 12, 26)
print(now_date)

# coding:utf-8
import datetime
print((2022, 12, 26))
print(type((2022, 12, 26))) # <class ''>
# The following code reports an error with a missing parameter
# print((2022, 12)) # TypeError: function missing required argument 'day' (pos 3)
# The following code suggests that the value is wrong, the date() function's parameters are, in order, year, month and day; the range of year is 1-9999, the range of month is 1-12, and the range of day is 1-31.
# print((10001, 12, 12)) # ValueError: year 10001 is out of range
# print((2022, 13, 12)) # ValueError: month must be in 1..12
# print((2022, 12, 32)) # ValueError: day is out of range for month
# keyword pass pass parameter, as long as you ensure that the value of the year, month, day are within the available range, the position is not affected
print((day=15, year=2029, month=12))

# coding:utf-8
import datetime
print(()) # 2022-07-08
print(type(())) # <class ''>

print((())) # Fri Jul 8 00:00:00 2022
print(type((()))) # <class 'str'>
# ctime() function's arguments must be Type
print(((2022, 12, 26))) # Mon Dec 26 00:00:00 2022

datetime_1 = (2022, 12, 26)
# Get the day of the date object, the value returned is of type int.
print(datetime_1.day, type(datetime_1.day), type(datetime_1)) # 26 <class 'int'> <class ''>
# Get the month of the date object, the value returned is also of type int.
print(datetime_1.month, type(datetime_1.month), type(datetime_1)) # 12 <class 'int'> <class ''>
# Get the year of the date object, the value returned is also of type int.
print(datetime_1.year, type(datetime_1.year), type(datetime_1)) # 2022 <class 'int'> <class ''>

datetime_1 = (2022, 12, 26)
print((datetime_1, year=2019, month=11, day=25)) # 2019-11-25
print(type((datetime_1, year=2019, month=11, day=25))) # <class ''>
print(datetime_1)
# Must have a date or time object parameter, not pass a replacement parameter that returns the value of the incoming object.
print((datetime_1)) # 2022-12-26
# Replacement year only
print((datetime_1, year=2019)) # 2019-12-26
# Replace only the month
print((datetime_1, month=11)) # 2022-11-26
# Replacement day only
print((datetime_1, day=25)) # 2022-12-25

datetime_2 = ()
print(datetime_2, type(datetime_2))
print((datetime_1, "%Y--%y--%D--%d--%H--%h--%M--%m--%S--%A--%a--%B--%b--%C--%c"))
print((datetime_2, "%Y--%y--%D--%d--%H--%h--%M--%m--%S--%A--%a--%B--%b--%C--%c"))
# Common formats: year, month, day, hour, minute, second
print((datetime_2, "%Y-%m-%d %H:%M:%S")) # 2022-07-08 18:32:40

# Returns the ISO standard date of a date or time object (4-digit year - 2-digit month - 2-digit day)
print((datetime_1), datetime_1) # 2022-12-26 2022-12-26
print((datetime_2), datetime_2) # 2022-07-08 2022-07-08 18:44:36.613676
# Convert date strings conforming to ISO standard format to objects
print(("2022-07-08"), type(("2022-07-08")))
# Errors are reported for date strings that do not conform to the ISO standard format.
# print(("2022-7-08")) # ValueError: Invalid isoformat string: '2022-7-08'
# print(("2022-07-8")) # ValueError: Invalid isoformat string: '2022-7-08'

print(((2022, 7, 3))) # 7 Sunday
print(((2022, 7, 4))) # 1 Monday
print(((2022, 7, 8))) # 5 Friday
print(((2022, 7, 9))) # 6 Saturdays

# Returns the day of the week (0~6) for a date or time object.
print(((2022, 7, 3))) # 6 Sunday
print(((2022, 7, 4))) # 0 Monday
print(((2022, 7, 8))) # 4 Friday
print(((2022, 7, 9))) # 5 Saturdays

print((2015236523)) # 2033-11-10
print(type((2015236523))) # <class ''>

# Get time tuples in ISO-compliant format
print(((2022, 7, 3))) # (year=2022, week=26, weekday=7)
# Calculate dates from time tuples (year, week, week number) in ISO standardized format.
print((2022, 26, 7)) # 2022-07-03

print((1), type((1))) # 0001-01-01 <class ''>
print((5)) # 0001-01-05
print((738339)) # 2022-07-03
# Returns the number of days from the beginning of the Gregorian calendar to the present day
print(((2022, 7, 3))) # 738339

# Convert date types to struct_time types
print(((2022, 7, 3)))
# Maximum value for date type
print()
# Minimum values for date types
print()

# coding:utf-8
import datetime
# Date object class (date class)
"""
* Date objects have3particular property：particular year、months、date
* date()It is possible to convert the specified three parameters to the type of the class
* date()Functions passing parameters by position must be：particular year、months、date的顺序
"""
print((2022, 12, 26))
print(type((2022, 12, 26))) # <class ''>
# The following code reports an error with a missing parameter
# print((2022, 12)) # TypeError: function missing required argument 'day' (pos 3)
# The following code suggests that the value is wrong, the date() function's parameters are, in order, year, month and day; the range of year is 1-9999, the range of month is 1-12, and the range of day is 1-31.
# print((10001, 12, 12)) # ValueError: year 10001 is out of range
# print((2022, 13, 12)) # ValueError: month must be in 1..12
# print((2022, 12, 32)) # ValueError: day is out of range for month
# keyword pass pass parameter, as long as you ensure that the value of the year, month, day are within the available range, the position is not affected
print((day=15, year=2029, month=12))
# Common functions of the date class
# Get current date
print(()) # 2022-07-08
print(type(())) # <class ''>
# ctime() is to convert an object to a datetime format string
print((())) # Fri Jul 8 00:00:00 2022
print(type((()))) # <class 'str'>
# ctime() function's arguments must be Type
print(((2022, 12, 26))) # Mon Dec 26 00:00:00 2022

# Create an object
datetime_1 = (2022, 12, 26)
# Get the day of the date object, the value returned is of type int.
print(datetime_1.day, type(datetime_1.day), type(datetime_1)) # 26 <class 'int'> <class ''>
# Get the month of the date object, the value returned is also of type int.
print(datetime_1.month, type(datetime_1.month), type(datetime_1)) # 12 <class 'int'> <class ''>
# Get the year of the date object, the value returned is also of type int.
print(datetime_1.year, type(datetime_1.year), type(datetime_1)) # 2022 <class 'int'> <class ''>
# Replace the value of the object
# replace(self, year=None, month=None, day=None) function has one mandatory argument and three default arguments
# year is the year to be replaced
# month is the month to be replaced
# day is the day to be replaced
print((datetime_1, year=2019, month=11, day=25)) # 2019-11-25
print(type((datetime_1, year=2019, month=11, day=25))) # <class ''>
print(datetime_1)
# Must have a date or time object parameter, not pass a replacement parameter that returns the value of the incoming object.
print((datetime_1)) # 2022-12-26
# Replacement year only
print((datetime_1, year=2019)) # 2019-12-26
# Replace only the month
print((datetime_1, month=11)) # 2022-11-26
# Replacement day only
print((datetime_1, day=25)) # 2022-12-25
# By observation, the replacement of year, month, and day are all based on 2022-12-26 (the initial value of the datetime_1 variable). So it is safe to assume that this function does not change the value of the source variable.
# Formatted date
datetime_2 = ()
print(datetime_2, type(datetime_2))
print((datetime_1, "%Y--%y--%D--%d--%H--%h--%M--%m--%S--%A--%a--%B--%b--%C--%c"))
print((datetime_2, "%Y--%y--%D--%d--%H--%h--%M--%m--%S--%A--%a--%B--%b--%C--%c"))
# Common formats: year, month, day, hour, minute, second
print((datetime_2, "%Y-%m-%d %H:%M:%S")) # 2022-07-08 18:32:40
# Returns the ISO standard date of a date or time object (4-digit year - 2-digit month - 2-digit day)
print((datetime_1), datetime_1) # 2022-12-26 2022-12-26
print((datetime_2), datetime_2) # 2022-07-08 2022-07-08 18:44:36.613676
# Convert date strings conforming to ISO standard format to objects
print(("2022-07-08"), type(("2022-07-08")))
# Errors are reported for date strings that do not conform to the ISO standard format.
# print(("2022-7-08")) # ValueError: Invalid isoformat string: '2022-7-08'
# print(("2022-07-8")) # ValueError: Invalid isoformat string: '2022-7-08'
# Get the day of the week (1~7) for a date string that conforms to the ISO standard format.
print(((2022, 7, 3))) # 7 Sunday
print(((2022, 7, 4))) # 1 Monday
print(((2022, 7, 8))) # 5 Friday
print(((2022, 7, 9))) # 6 Saturday
# Returns the day of the week (0~6) for a date or time object.
print(((2022, 7, 3))) # 6 Sunday
print(((2022, 7, 4))) # 0 Monday
print(((2022, 7, 8))) # 4 Friday
print(((2022, 7, 9))) # 5 Saturday
# Calculate dates based on timestamps
print((2015236523)) # 2033-11-10
print(type((2015236523))) # <class ''>
# Get a time tuple in ISO standardized format (year, week, week number)
# Weeks: weeks of the year, range 1-53
# of weeks: the first day of the week, Monday is day 1, Sunday is day 7
print(((2022, 7, 3))) # (year=2022, week=26, weekday=7)
# Calculate dates from time tuples (year, week, week number) in ISO standardized format.
print((2022, 26, 7)) # 2022 -07-03
# Convert shaping to date by A.D. calendar
# * January 1, A.D. 1 for 1
print((1), type((1))) # 0001-01-01 <class ''>
print((5)) # 0001-01-05
print((738339)) # 2022-07-03
# Returns the number of days from the beginning of the Gregorian calendar to the present day
print(((2022, 7, 3))) # 738339
# Convert date types to struct_time types
print(((2022, 7, 3)))
# Maximum value for date type
print()
# Minimum values for date types
print()