In python, this is usually done through thedict
cap (a poem)zip
combinations to build key-value pairs.
For example:
aid = [i for i in range(10)] name = [[1] * 3] * len(aid) dic1 = dict(zip(aid,name)) print('dic1:', dic1)
Get:
{0: [1, 1, 1],
1: [1, 1, 1],
2: [1, 1, 1],
3: [1, 1, 1],
4: [1, 1, 1],
5: [1, 1, 1],
6: [1, 1, 1],
7: [1, 1, 1],
8: [1, 1, 1],
9: [1, 1, 1]}
This establishes theaid
cap (a poem)name
of the one-to-one mapping relationship, using the aid as the key and the second column as the value.
It can also be accessed through thedic
function of the form or{}
direct construction
dic2 = {'aid': aid,'name':name} print('\ndic2:',dic2)
{
‘aid’: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
‘name’: [[1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1]]
}
This way by creating a new key, the list is stored as a value.
The above two methods, if you want to go through the aids for indexing to get the corresponding value:
Method 1 can be taken out directly, method 2 still need to get to the index and then take the value. So method 1 is faster but in contrast, method 1 stores many key-value pairs, which is not as good as method 2 in terms of storage space.
The space occupancy tests are as follows:
aid = [i for i in range(10)] name = [[1] * 3] * len(aid) dic1 = dict(zip(aid,name)) dic2 = {'aid': aid,'name':name} print('dic1:', dic1) print((dic1)) print('\ndic2:',dic2) print((dic2))
dic1: {0: [1, 1, 1], 1: [1, 1, 1], 2: [1, 1, 1], 3: [1, 1, 1], 4: [1, 1, 1], 5: [1, 1, 1], 6: [1, 1, 1], 7: [1, 1, 1], 8: [1, 1, 1], 9: [1, 1, 1]} 360 dic2: {'aid': [0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 'name': [[1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1], [1, 1, 1]]} 232
After testing, the dictionary footprint and the number of key-value pairs are not linear. If in a very large data, you need to consider the size of the occupied space, for example. 10000 key-value pairs, occupied 7w bytes. (Applied in saving embeddings offline)
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