This article example describes the Python method to remove duplicate elements from a list. Shared for your reference. Specific as follows:
Easier to remember is to use the built-in set
l1 = ['b','c','d','b','c','a','a'] l2 = list(set(l1)) print l2
There's also one that's supposedly faster, haven't tested the speed difference between the two
l1 = ['b','c','d','b','c','a','a'] l2 = {}.fromkeys(l1).keys() print l2
Both of these have a drawback, the ordering changes after getting rid of duplicate elements:
['a', 'c', 'b', 'd']
If you want to keep them in their original order:
Use the sort method of the list class
l1 = ['b','c','d','b','c','a','a'] l2 = list(set(l1)) (key=) print l2
It can also be written like this
l1 = ['b','c','d','b','c','a','a'] l2 = sorted(set(l1),key=) print l2
It is also possible to use the traversal
l1 = ['b','c','d','b','c','a','a'] l2 = [] for i in l1: if not i in l2: (i) print l2
The above code could also be written like this
l1 = ['b','c','d','b','c','a','a'] l2 = [] [(i) for i in l1 if not i in l2] print l2
This ensures that the ordering remains the same:
['b', 'c', 'd', 'a']
I hope that what I have described in this article will help you in your Python programming.