Python implementation of determining if a given list has duplicate elements

This article example describes the Python implementation of determining whether a given list has duplicate elements. Shared for your reference, as follows:

The topic is very simple, just a brief refresher on a method, most_common, which is a method of the Counter class in the collection module, and the specific method usage can be found in the

Here is a simple implementation:

#!usr/bin/env python
#encoding:utf-8
'''''
__Author__:Yishui Cold City
Function: Given a list determine if there are any duplicate elements in it.
'''
from collections import Counter
def func1(num_list):
  '''''
  Use the set method directly
  '''
  if len(num_list)!=len(set(num_list)):
    print 'have duplicates!!!'
  else:
    print 'no duplicates!!'
def func2(num_list):
  '''''
  Using the Counter class with collections
  '''
  cou=Counter(num_list)
  first=cou.most_common(1)
  if first[0][1]>1:
    print 'have duplicates!!!'
  else:
    print 'no duplicates!!'
if __name__ == '__main__':
  num_list=[[1,2,3,4],[6,7,8],[4,5,6,6,6]]
  print 'I test results:'
  for one_list in num_list:
    print 'one_list', one_list
    func1(one_list)
    func2(one_list)

The results are as follows:

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Online character counting and editing tool:
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I hope that what I have said in this article will help you in Python programming.