Using the sorted() function
Use the sorted() function to sort a dictionary into a list of tuples, which are then sorted by the specified key or value.
Sample code for sorting by key
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
sorted_d = dict(sorted((), key=lambda x: x[0]))
print(sorted_d)The results are as follows:
Sample code for sorting by value
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
sorted_d = dict(sorted((), key=lambda x: x[1]))
print(sorted_d)The results are as follows:
Using the itemgetter() function
You can use the operator module's itemgetter() function to sort a dictionary, convert it to a list of tuples, and then sort it by the specified key or value.
Sample code for sorting by key
from operator import itemgetter
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
sorted_d = dict(sorted((), key=itemgetter(0)))
print(sorted_d)The results are as follows:
Sample code for sorting by value
from operator import itemgetter
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
sorted_d = dict(sorted((), key=itemgetter(1)))
print(sorted_d)The results are as follows:
Using the OrderedDict Class
Dictionaries can be sorted using the OrderedDict class of the collections module.OrderedDict is an ordered dictionary that preserves the order in which elements are inserted.
Sample code for sorting by key
from collections import OrderedDict
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
sorted_d = OrderedDict(sorted((), key=lambda x: x[0]))
print(sorted_d)The results are as follows:
Sample code for sorting by value
from collections import OrderedDict
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
sorted_d = OrderedDict(sorted((), key=lambda x: x[1]))
print(sorted_d)The results are as follows:
Using the zip() function
You can use the zip() function to convert the keys and values of a dictionary to a list, then sort the list by the specified key or value, and finally reassemble the dictionary from the sorted keys and values.
Sample code for sorting by key
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
keys = list(())
values = list(())
sorted_keys = sorted(keys)
sorted_values = [d[k] for k in sorted_keys]
sorted_d = dict(zip(sorted_keys, sorted_values))
print(sorted_d)The results are as follows:
Sample code for sorting by value
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
keys = list(())
values = list(())
sorted_values = sorted(values)
sorted_keys = [keys[(v)] for v in sorted_values]
sorted_d = dict(zip(sorted_keys, sorted_values))
print(sorted_d)The results are as follows:
Using the Pandas Library
You can use the Pandas library to convert a dictionary to a DataFrame, then sort it by a specified key or value, and finally convert the sorted DataFrame to a dictionary.
Sample code for sorting by key
import pandas as pd
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
df = (list(()), columns=['fruit', 'count'])
sorted_df = df.sort_values('fruit')
sorted_d = dict(zip(sorted_df['fruit'], sorted_df['count']))
print(sorted_d)The results are as follows:
Sample code for sorting by value
import pandas as pd
d = {'apple': 4, 'banana': 2, 'pear': 1, 'orange': 3}
df = (list(()), columns=['fruit', 'count'])
sorted_df = df.sort_values('count')
sorted_d = dict(zip(sorted_df['fruit'], sorted_df['count']))
print(sorted_d)The results are as follows:
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