python path splicing
Use:
- () function: connects two or more pathname components
- If one component is an absolute path, all components before it are discarded.
- If the last component is empty, the generated path ends with a \ separator
def test2(): s1, s2, s3 = 'home', 'courses', 'test' res = (s1, s2, s3) print(res) # home\courses\test s2 = '/courses' res = (s1, s2, s3) print(res) # /courses\test s1, s2, s3 = '\home', 'courses', 'test' res = (s1, s2, s3) print(res) # \home\courses\test s1, s2, s3 = '\home', 'courses', '' res = (s1, s2, s3) print(res) #\home\courses\
home\courses\test
/courses\test
\home\courses\test
\home\courses\
python path splicing error
ss = 'E:\\Cloud\\20200813105812L\\res\\1\\425' a = '\\8_live_1962854245_export_files\\media' c = (ss,a) print(c)
The following result is obtained:
() function
Connects two or more pathname components:
There may be more than one parameter
Start counting from the right, encounter the first parameter starting with "/", start splicing, the parameter to the left of all the discarded
print("0:",('\\aaaa','bbbb',''))
print("0:",('aaaa','\\bbbb',''))
print("0:",('aaaa','bbbb','\\'))
print("0:",('aaaa','\\bbbb','\\'))
print("0:",('aaaa','/bbbb','\\'))
print("0:",('aaaa','/bbbb','/'))
in the end：
0: \aaaa\bbbb\
0: \bbbb\
0: \
0: \
0: \
0: /
Start counting from the right, encounter the first parameter starting with "/", start splicing, the parameter to the left of all the discarded
print("1:",('aaaa','xxxxxx','./bbb',''))
print("1:",('./aaaa','xxxxxx','./bbb','./'))
in the end：
1: aaaa\xxxxxx\./bbb\
1: ./aaaa\xxxxxx\./bbb\./
With disk symbols,/,\, a variety of complex situations (before the official use of the test, you can also go to see the source code to see exactly how to parse)
# Backslash backslash
print("1:",('c:','bbb'))
print("1:",('c:','bbb/\\',''))
# Undisked
print("2:",('c','/bbb','')) # Will start with /bbb
print("2:",('c:','/bbb','')) # There's a backslash, but it still starts with a C: #
print("2:",('c:/','/bbb','')) # Multiple/only one
# No slash after the disk drive
print("3:",('c:','bbb',''))
print("3:",('c:/','bbb',''))
in the end:
1: c:bbb
1: c:bbb/\
2: /bbb\
2: c:/bbb\
2: c:/bbb\
3: c:bbb\
3: c:/bbb\
summarize
The above is a personal experience, I hope it can give you a reference, and I hope you can support me more.